In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line.One may conclude that:

\({\rm{R}}\left( {\rm{T}} \right) = {{\rm{R}}_0}{{\rm{e}}^{ - {{\rm{T}}^2}/{\rm{T}}_0^2}}\)

\({\rm{R}}\left( {\rm{T}} \right) = \frac{{{{\rm{R}}_0}}}{{{{\rm{T}}^2}}}\)

\({\rm{R}}\left( {\rm{T}} \right) = {{\rm{R}}_0}{{\rm{e}}^{ - {\rm{T}}_0^2/{{\rm{T}}^2}}}\)

\({\rm{R}}\left( {\rm{T}} \right) = {{\rm{R}}_0}{{\rm{e}}^{{{\rm{T}}^2}/{\rm{T}}_0^2}}\)

In an experiment, the resistance of a material is plotted as a functio

1.	In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line.One may conclude that:
A.	\({\rm{R}}\left( {\rm{T}} \right) = \frac{{{{\rm{R}}_0}}}{{{{\rm{T}}^2}}}\)
B.	\({\rm{R}}\left( {\rm{T}} \right) = {{\rm{R}}_0}{{\rm{e}}^{ - {\rm{T}}_0^2/{{\rm{T}}^2}}}\)
C.	\({\rm{R}}\left( {\rm{T}} \right) = {{\rm{R}}_0}{{\rm{e}}^{ - {{\rm{T}}^2}/{\rm{T}}_0^2}}\)
D.	\({\rm{R}}\left( {\rm{T}} \right) = {{\rm{R}}_0}{{\rm{e}}^{{{\rm{T}}^2}/{\rm{T}}_0^2}}\)
Answer» C. \({\rm{R}}\left( {\rm{T}} \right) = {{\rm{R}}_0}{{\rm{e}}^{ - {{\rm{T}}^2}/{\rm{T}}_0^2}}\)

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In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line.One may conclude that:

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