In a triangle \(PQR\), \(PS\) is the angle bisector of \(\angle QPR\) and \(\angle QPS = 60\). What is thelength of \(PS\)?

\(\sqrt {\left( {{q^2} + {r^r}} \right)}\)

\(\frac{{\left( {q + r} \right)}}{{qr}}\)

\(\frac{{qr}}{{\left( {q + r} \right)}}\)

\(\frac{{{{\left( {q + r} \right)}^2}}}{{qr}}\)

In a triangle \(PQR\), \(PS\) is the angle bisector of \(\angle QPR\)

1.	In a triangle \(PQR\), \(PS\) is the angle bisector of \(\angle QPR\) and \(\angle QPS = 60\). What is thelength of \(PS\)?
A.	\(\frac{{\left( {q + r} \right)}}{{qr}}\)
B.	\(\frac{{qr}}{{\left( {q + r} \right)}}\)
C.	\(\sqrt {\left( {{q^2} + {r^r}} \right)}\)
D.	\(\frac{{{{\left( {q + r} \right)}^2}}}{{qr}}\)
Answer» C. \(\sqrt {\left( {{q^2} + {r^r}} \right)}\)

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In a triangle \(PQR\), \(PS\) is the angle bisector of \(\angle QPR\) and \(\angle QPS = 60\). What is thelength of \(PS\)?

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