In a triangle ABC, if angle B = \[90{}^\circ \] and D is the point in BC such that BD = 2 DC, then

\[A{{C}^{2}}=\,A{{D}^{2}}+7C{{D}^{2}}\]

\[A{{C}^{2}}=\,A{{D}^{2}}+3C{{D}^{2}}\]

\[A{{C}^{2}}=\,A{{D}^{2}}+5C{{D}^{2}}\]

\[A{{C}^{2}}=\,A{{B}^{2}}+5B{{D}^{2}}\]

In a triangle ABC, if angle B = \[90{}^\circ \] and D is the point in

1.	In a triangle ABC, if angle B = \[90{}^\circ \] and D is the point in BC such that BD = 2 DC, then
A.	\[A{{C}^{2}}=\,A{{D}^{2}}+3C{{D}^{2}}\]
B.	\[A{{C}^{2}}=\,A{{D}^{2}}+5C{{D}^{2}}\]
C.	\[A{{C}^{2}}=\,A{{D}^{2}}+7C{{D}^{2}}\]
D.	\[A{{C}^{2}}=\,A{{B}^{2}}+5B{{D}^{2}}\]
Answer» C. \[A{{C}^{2}}=\,A{{D}^{2}}+7C{{D}^{2}}\]