1.

In a triangle ABC, a – 2b + c = 0. The value of \(\cot \left( {\frac{A}{2}} \right)\cot \left( {\frac{C}{2}} \right)\) is

A. \(\frac{9}{2}\)
B. 3
C. \(\frac{3}{2}\)
D. 1
Answer» C. \(\frac{3}{2}\)


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