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| 1. |
In a right angled triangle ABC, if the hypotenuse AC = p, then what is \(\overrightarrow {{\rm{AB}}} \cdot \overrightarrow {{\rm{AC}}} + \overrightarrow {{\rm{BC}}} \cdot \overrightarrow {{\rm{BA}}} + \overrightarrow {{\rm{CA}}} \cdot \overrightarrow {{\rm{CB}}} \) equal to? |
| A. | p |
| B. | p2 |
| C. | 2p2 |
| D. | \(\frac{{{{\rm{p}}^2}}}{2}\) |
| Answer» C. 2p2 | |