1.

In a quadrilateral ABCD, if the diagonals AC,BD intersect at right angles, then

A. \[A{{B}^{2}}+B{{C}^{2}}=D{{C}^{2}}+D{{A}^{2}}\]
B. \[A{{B}^{2}}+C{{D}^{2}}=B{{C}^{2}}+D{{A}^{2}}\]
C. \[A{{B}^{2}}+A{{D}^{2}}=C{{B}^{2}}+C{{D}^{2}}\]
D. \[A{{B}^{2}}+B{{C}^{2}}=2(D{{C}^{2}}+D{{A}^{2}})\]
Answer» C. \[A{{B}^{2}}+A{{D}^{2}}=C{{B}^{2}}+C{{D}^{2}}\]


Discussion

No Comment Found

Related MCQs