MCQOPTIONS
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| 1. |
In a circle, AB is a the diameter and CD is a chord. AB and CD produced meet at a point P, outside the circle. If PD = 15.3 cm, CD =11.9 cm and AP = 30.6 cm, then the radius of the circle is is:_x005F_x000D_ Â _x005F_x000D_ |
| A. | 8 cm |
| B. | 8.5 cm |
| C. | 9cm |
| D. | 7.5 cm |
| Answer» C. 9cm | |