In a binomial distribution, the mean is \(\dfrac{2}{3}\) and variance is \(\dfrac{5}{9}\). What is the probability that random variable D = 2?

In a binomial distribution, the mean is \(\dfrac{2}{3}\) and variance

1.	In a binomial distribution, the mean is \(\dfrac{2}{3}\) and variance is \(\dfrac{5}{9}\). What is the probability that random variable D = 2?
A.	\(\dfrac{5}{36}\)
B.	\(\dfrac{25}{36}\)
C.	\(\dfrac{25}{54}\)
D.	\(\dfrac{25}{216}\)
Answer» E.

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In a binomial distribution, the mean is \(\dfrac{2}{3}\) and variance is \(\dfrac{5}{9}\). What is the probability that random variable D = 2?

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