If \(y = {\tan ^{ - 1}}\left( {\frac{{5 - 2\tan \sqrt x }}{{2 + 5\tan \sqrt x }}} \right)\) then what is \(\frac{{dy}}{{dx}}\) equal to?

If \(y = {\tan ^{ - 1}}\left( {\frac{{5 - 2\tan \sqrt x }}{{2 + 5\tan

1.	If \(y = {\tan ^{ - 1}}\left( {\frac{{5 - 2\tan \sqrt x }}{{2 + 5\tan \sqrt x }}} \right)\) then what is \(\frac{{dy}}{{dx}}\) equal to?
A.	\( - \frac{1}{{2\sqrt x }}\)
B.	1
C.	-1
D.	\(\frac{1}{{2\sqrt x }}\)
Answer» B. 1

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If \(y = {\tan ^{ - 1}}\left( {\frac{{5 - 2\tan \sqrt x }}{{2 + 5\tan \sqrt x }}} \right)\) then what is \(\frac{{dy}}{{dx}}\) equal to?

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