If y = (sin-1x)2 then:

1.	If y = (sin-1x)2 then:
A.	(1 - x2)yn + 2 - (2n + 1)xyn + 1 - n2yn = 0
B.	(1 - x2)yn + 2 - (2n + 1)xyn + 1 + n2yn = 0
C.	(1 - x2)yn + 2 + (2n + 1)xyn + 1 - n2yn = 0
D.	(1 - x2)yn + 2 - (2n - 1)xyn + 1 - n2yn = 0
Answer» B. (1 - x2)yn + 2 - (2n + 1)xyn + 1 + n2yn = 0

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If y = (sin-1x)2 then:

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