If \[x=\sqrt[3]{2+\sqrt{3}}\],then \[{{\mathbf{x}}^{\mathbf{3}}}+\frac{1}{{{\mathbf{x}}^{\mathbf{3}}}},=\]

If \[x=\sqrt[3]{2+\sqrt{3}}\],then \[{{\mathbf{x}}^{\mathbf{3}}}+\frac

1.	If \[x=\sqrt[3]{2+\sqrt{3}}\],then \[{{\mathbf{x}}^{\mathbf{3}}}+\frac{1}{{{\mathbf{x}}^{\mathbf{3}}}},=\]
A.	2
B.	4
C.	8
D.	9
Answer» C. 8

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If \[x=\sqrt[3]{2+\sqrt{3}}\],then \[{{\mathbf{x}}^{\mathbf{3}}}+\frac{1}{{{\mathbf{x}}^{\mathbf{3}}}},=\]

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