1.

If \[X=\frac{a-b}{a+b}.y=\frac{b-c}{b+c},Z=\frac{c-a}{c+a},\]then the value of \[\frac{(1+x)(1+y)(1+z)}{(1-x)(1-y)(1-z)}\]is _______.

A.  \[abc\]                         
B. \[{{a}^{2}}{{b}^{2}}{{c}^{2}}\]    
C.         1                    
D.        \[-1\]
Answer» D.        \[-1\]


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