If \(x+\frac{1}{y+\frac{1}{z~-~\frac{1}{5}}}=\frac{130}{53}\), where x – McqOptions

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1.	If \(x+\frac{1}{y+\frac{1}{z~-~\frac{1}{5}}}=\frac{130}{53}\), where x, y, and z are natural numbers, then the value of (3x – 2y + z) is:
A.	4
B.	5
C.	6
D.	7
Answer» E.

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