If \(x + \frac{1}{x}\; = \;6,x \ne 0,\) then the value of \(\frac{{{x^2} + \;3x\; + \;1}}{{{x^4}\; + \;{x^{ - 2}}}}\) is:

• A. \(\frac{1}{{12}}\)
• B. \(\frac{1}{{14}}\)
• C. \(\frac{1}{{24}}\)
• D. \(\frac{1}{{22}}\)