If\[x=2.\overline{3}-0.\overline{9},\,y=2.\overline{5}-0.\overline{5},\]then \[{{x}^{2}}+{{y}^{2}}-2xy\] is

If\[x=2.\overline{3}-0.\overline{9},\,y=2.\overline{5}-0.\overline{5},

1.	If\[x=2.\overline{3}-0.\overline{9},\,y=2.\overline{5}-0.\overline{5},\]then \[{{x}^{2}}+{{y}^{2}}-2xy\] is
A.	\[\frac{1}{4}\]
B.	\[\frac{1}{3}\]
C.	\[\frac{1}{2}\]
D.	\[\frac{1}{5}\]
Answer» B. \[\frac{1}{3}\]

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If\[x=2.\overline{3}-0.\overline{9},\,y=2.\overline{5}-0.\overline{5},\]then \[{{x}^{2}}+{{y}^{2}}-2xy\] is

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