If \({x^2} + \frac{1}{{{x^2}}} = 6\), then find the value of \(\frac{{ – McqOptions

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1.	If \({x^2} + \frac{1}{{{x^2}}} = 6\), then find the value of \(\frac{{2x\left( {x - 1} \right)}}{{{x^3} - {x^2} - x + 1}}\)
A.	0
B.	1
C.	2
D.	3
Answer» C. 2

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