If x ≠ -1, 2 and 5, then the simplified value of \(\frac{{2\left( {{x^3} - 8} \right)}}{{{x^2} - x - 2}}\; \times \;\frac{{{x^2}\; + \;2x\; + \;1}}{{{x^2} - 4x - 5}} \div \;\frac{{{x^2}\; + \;2x\; + \;4}}{{3x - 15}}\) is equal to:

• A. 16
• B. 6
• C. 32
• D. 23