If u = eax sin bx and v = eax cos bx, then what is \({\rm{u}}\frac{{{\rm{du}}}}{{{\rm{dx}}}} + {\rm{v}}\frac{{{\rm{dv}}}}{{{\rm{dx}}}}\) equal to?

If u = eax sin bx and v = eax cos bx, then what is \({\rm{u}}\frac{{{\

1.	If u = eax sin bx and v = eax cos bx, then what is \({\rm{u}}\frac{{{\rm{du}}}}{{{\rm{dx}}}} + {\rm{v}}\frac{{{\rm{dv}}}}{{{\rm{dx}}}}\) equal to?
A.	a e2ax
B.	(a2 + b2)eax
C.	ab e2ax
D.	(a + b)eax
Answer» B. (a2 + b2)eax

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If u = eax sin bx and v = eax cos bx, then what is \({\rm{u}}\frac{{{\rm{du}}}}{{{\rm{dx}}}} + {\rm{v}}\frac{{{\rm{dv}}}}{{{\rm{dx}}}}\) equal to?

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