MCQOPTIONS
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| 1. |
If the tangent to the curve \(y = \frac{x}{{{x^2} - 3}},\;x \in {\rm{R}},\left( {x \ne \pm \sqrt 3 } \right),{\rm{\;}}\)at a point (α, β) ≠ (0, 0) on it is parallel to the line 2x + 6y - 11 = 0, then: |
| A. | |6α + 2β| = 19 |
| B. | |6α + 2β| = 9 |
| C. | |2α + 6β| = 19 |
| D. | |2α + 6β| = 11 |
| Answer» B. |6α + 2β| = 9 | |