If the system of equation 2x + 3y + 5 = 0, x + ky + 5 = 0, kx - 12y - 14 = 0 be consistent, then the values of k are -

If the system of equation 2x + 3y + 5 = 0, x + ky + 5 = 0, kx - 12y -

1.	If the system of equation 2x + 3y + 5 = 0, x + ky + 5 = 0, kx - 12y - 14 = 0 be consistent, then the values of k are -
A.	\(6, \ \dfrac{-17}{5}\)
B.	\(-1, \ \dfrac{1}{5}\)
C.	\(-6, \ \dfrac{17}{5}\)
D.	\(6, \ \dfrac{-12}{5}\)
Answer» B. \(-1, \ \dfrac{1}{5}\)

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If the system of equation 2x + 3y + 5 = 0, x + ky + 5 = 0, kx - 12y - 14 = 0 be consistent, then the values of k are -

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