If the mean of \[{{x}_{1}}\] and that of \[{{x}_{1}},{{x}_{2}}{{x}_{3}},{{x}_{4}}\] is \[{{M}_{2}}\]the mean of \[{{x}_{1}},\]\[{{x}_{2}}\text{/}a,\]\[{{x}_{3}}+a,\]\[{{x}_{4}}-a\]is

\[{{M}_{1}}+\frac{(a-1)\,{{x}_{1}}-2{{M}_{2}}}{4a}\]

\[{{M}_{1}}+\frac{(a-1)({{x}_{1}}-2{{M}_{1}})}{4a}\]

\[\frac{{{M}_{2}}}{4a}+(a-1){{x}_{1}}+2{{M}_{1}}\]

\[\frac{{{M}_{1}}}{4a}+(a-1){{x}_{2}}+2{{M}_{2}}\]

If the mean of \[{{x}_{1}}\] and that of \[{{x}_{1}},{{x}_{2}}{{x}_{3}

1.	If the mean of \[{{x}_{1}}\] and that of \[{{x}_{1}},{{x}_{2}}{{x}_{3}},{{x}_{4}}\] is \[{{M}_{2}}\]the mean of \[{{x}_{1}},\]\[{{x}_{2}}\text{/}a,\]\[{{x}_{3}}+a,\]\[{{x}_{4}}-a\]is
A.	\[{{M}_{1}}+\frac{(a-1)({{x}_{1}}-2{{M}_{1}})}{4a}\]
B.	\[{{M}_{1}}+\frac{(a-1)\,{{x}_{1}}-2{{M}_{2}}}{4a}\]
C.	\[\frac{{{M}_{2}}}{4a}+(a-1){{x}_{1}}+2{{M}_{1}}\]
D.	\[\frac{{{M}_{1}}}{4a}+(a-1){{x}_{2}}+2{{M}_{2}}\]
Answer» B. \[{{M}_{1}}+\frac{(a-1)\,{{x}_{1}}-2{{M}_{2}}}{4a}\]

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If the mean of \[{{x}_{1}}\] and that of \[{{x}_{1}},{{x}_{2}}{{x}_{3}},{{x}_{4}}\] is \[{{M}_{2}}\]the mean of \[{{x}_{1}},\]\[{{x}_{2}}\text{/}a,\]\[{{x}_{3}}+a,\]\[{{x}_{4}}-a\]is

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