If $${\text{se}}{{\text{c}}^2}\theta+ {\text{ta}}{{\text{n}}^2}\theta= \frac{7}{{12}}{\text{,}}$$then $${\text{se}}{{\text{c}}^4}\theta $$- $${\text{ta}}{{\text{n}}^4}\theta $$= ?

• A. $\frac{7}{{12}}$$
• B. $\frac{1}{2}$$
• C. $\frac{7}{2}$$