1.

If \(\tan x=\dfrac{b}{a}\), then \(\sqrt{\dfrac{a+b}{a-b}}+\sqrt{\dfrac{a-b}{a+b}}\) is equal to :

A. \(\dfrac{2 \sin x}{\sqrt{\sin 2x}}\)
B. \(\dfrac{2 \cos x}{\sqrt{\cos 2x}}\)
C. \(\dfrac{2 \cos x}{\sqrt{\sin 2x}}\)
D. \(\dfrac{2\sin x}{\sqrt{\cos 2x}}\)
Answer» C. \(\dfrac{2 \cos x}{\sqrt{\sin 2x}}\)


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