If \[\sqrt[3]{3\left( \sqrt[3]{x}-\frac{1}{\sqrt[3]{x}} \right)}=2\], then \[\sqrt[3]{x}+\frac{1}{\sqrt[3]{x}}=\_\_\_\_\_\].

• A.  \[\frac{10}{3}\]                     
• B.        \[-\frac{10}{3}\]        
• C.  \[\frac{3}{15}\]                     
• D.         Both [a] and [b]