1.

If sinθ = $$\frac{a}{b}$$then the value of secθ - cosθ is? (where 0° < θ < 90°)

A. $\frac{a}{{b\sqrt {{b^2} - {a^2}} }}$$
B. $\frac{{{b^2}}}{{a\sqrt {{b^2} - {a^2}} }}$$
C. $\frac{{{a^2}}}{{b\sqrt {{b^2} - {a^2}} }}$$
D. $\frac{{\sqrt {{b^2} + {a^2}} }}{{\sqrt {{b^2} - {a^2}} }}$$
Answer» D. $\frac{{\sqrt {{b^2} + {a^2}} }}{{\sqrt {{b^2} - {a^2}} }}$$


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