If sinθ = 3x and cosθ = 3/x, (x ≠ 0) then the value of 6(x2 + 1/x2 – McqOptions

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1.	If sinθ = 3x and cosθ = 3/x, (x ≠ 0) then the value of 6(x2 + 1/x2) is:
A.	1/3
B.	1/4
C.	2/3
D.	1/2
Answer» D. 1/2

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