MCQOPTIONS
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| 1. |
If secθ + tanθ = x then secθ |
| A. | \(\frac{{{x^2} - 1}}{{2x}}\) |
| B. | \(\frac{{{x^2} + 1}}{x}\) |
| C. | \(\frac{{{x^2} - 1}}{x}\) |
| D. | \(\frac{{{x^2} + 1}}{{2x}}\) |
| Answer» E. | |