If $$sec\theta= x + \frac{1}{{4x}}$$$$\left( {{0^ \circ } < \theta< {{ – McqOptions

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1.	If $$sec\theta= x + \frac{1}{{4x}}$$$$\left( {{0^ \circ } < \theta< {{90}^ \circ }} \right)$$then $$sec\theta $$+ $${\text{tan}}\theta $$is equal to?
A.	$\frac{x}{2}$$
B.	x
C.
Answer» C.

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