If \[sec\theta +tan\theta =x,(x\ne 0)\]then \[\mathbf{sec}\theta \]is equal to

\[\left( x-\frac{1}{x} \right),x\ne 0\]

\[2\left( x-\frac{1}{x} \right),x\ne 0\]

\[\left( x+\frac{1}{x} \right),x\ne 0\]

\[\frac{1}{2}\left( x+\frac{1}{x} \right),x\ne 0\]

If \[sec\theta +tan\theta =x,(x\ne 0)\]then \[\mathbf{sec}\theta \]is

1.	If \[sec\theta +tan\theta =x,(x\ne 0)\]then \[\mathbf{sec}\theta \]is equal to
A.	\[\left( x-\frac{1}{x} \right),x\ne 0\]
B.	\[2\left( x-\frac{1}{x} \right),x\ne 0\]
C.	\[\left( x+\frac{1}{x} \right),x\ne 0\]
D.	\[\frac{1}{2}\left( x+\frac{1}{x} \right),x\ne 0\]
Answer» E.

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If \[sec\theta +tan\theta =x,(x\ne 0)\]then \[\mathbf{sec}\theta \]is equal to

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