If \(sec\theta = \frac{a}{b},b \ne 0,then\frac{{1 - {{\tan }^2}\theta }}{{2 - {{\sin }^2}\theta }}\)=?

\(\frac{{{a^2}\left( {2{b^2} - {a^2}} \right)}}{{{a^2}\left( {{a^2} - {b^2}} \right)}}\)

\(\frac{{{b^2}\left( {2{b^2} - {a^2}} \right)}}{{{a^2}\left( {{a^2} + {b^2}} \right)}}\)

\(\frac{{{b^2}\left( {2{b^2} + {a^2}} \right)}}{{{a^2}\left( {{a^2} + {b^2}} \right)}}\)

\(\frac{{{a^2}\left( {2{b^2} - {a^2}} \right)}}{{{b^2}\left( {{a^2} + {b^2}} \right)}}\)

If \(sec\theta = \frac{a}{b},b \ne 0,then\frac{{1 - {{\tan }^2}\theta

1.	If \(sec\theta = \frac{a}{b},b \ne 0,then\frac{{1 - {{\tan }^2}\theta }}{{2 - {{\sin }^2}\theta }}\)=?
A.	\(\frac{{{b^2}\left( {2{b^2} - {a^2}} \right)}}{{{a^2}\left( {{a^2} + {b^2}} \right)}}\)
B.	\(\frac{{{b^2}\left( {2{b^2} + {a^2}} \right)}}{{{a^2}\left( {{a^2} + {b^2}} \right)}}\)
C.	\(\frac{{{a^2}\left( {2{b^2} - {a^2}} \right)}}{{{b^2}\left( {{a^2} + {b^2}} \right)}}\)
D.	\(\frac{{{a^2}\left( {2{b^2} - {a^2}} \right)}}{{{a^2}\left( {{a^2} - {b^2}} \right)}}\)
Answer» D. \(\frac{{{a^2}\left( {2{b^2} - {a^2}} \right)}}{{{a^2}\left( {{a^2} - {b^2}} \right)}}\)