1.

If sec θ – tan θ = x/y, (0 < x < y) and 0°< θ < 90°, then sinθ is equal to:

A. \(\frac{{{y^2} - {x^2}}}{{{x^2} + {y^2}}}\)
B. \(\frac{{{x^2} + {y^2}}}{{{y^2} - {x^2}}}\)
C. \(\frac{{2xy}}{{{x^2} + {y^2}}}\)
D. \(\frac{{{x^2} + {y^2}}}{{2xy}}\)
Answer» B. \(\frac{{{x^2} + {y^2}}}{{{y^2} - {x^2}}}\)


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