MCQOPTIONS
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| 1. |
If sec θ – tan θ = P, then cosec θ = ? |
| A. | \(\frac{{{{\rm{P}}^2} + 1}}{{1 - {{\rm{P}}^2}}}\) |
| B. | \(\frac{{1 - {{\rm{P}}^2}}}{{1 + {{\rm{P}}^2}}}\) |
| C. | \(\frac{{2{\rm{P}}}}{{1 - {{\rm{P}}^2}}}\) |
| D. | \(\frac{{2{\rm{P}}}}{{1 + {{\rm{P}}^2}}}\) |
| Answer» B. \(\frac{{1 - {{\rm{P}}^2}}}{{1 + {{\rm{P}}^2}}}\) | |