1.

If sec θ + tan θ = m (>1), then the value of sin θ is (0° < θ < 90°)

A. \(\frac{{1 - {m^2}}}{{1 + {m^2}}}\)
B. \(\frac{{{m^2} - 1}}{{{m^2} + 1}}\)
C. \(\frac{{{m^2} + 1}}{{{m^2} - 1}}\)
D. \(\frac{{1 + {m^2}}}{{1 - {m^2}}}\)
Answer» C. \(\frac{{{m^2} + 1}}{{{m^2} - 1}}\)


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