If sec θ = 8 x and tan θ = 8/x (x ≠ 0), then the value of 16 (x2 � – McqOptions

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1.	If sec θ = 8 x and tan θ = 8/x (x ≠ 0), then the value of 16 (x2 − 1/x2) is:
A.	1/4
B.	1/16
C.	1/2
D.	1/3
Answer» B. 1/16

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