If pqr ≠ 0 and \({{p}^{-x}}=\frac{1}{q}~,~{{q}^{-y}}=\frac{1}{r}\text{ }\!\!~\!\!\text{ },\text{ }\!\!~\!\!\text{ }{{r}^{-z}}=\frac{1}{p}\text{ }\!\!~\!\!\text{ },\text{ }\!\!~\!\!\text{ }\)What is the value of the product of xyz?

If pqr ≠ 0 and \({{p}^{-x}}=\frac{1}{q}~,~{{q}^{-y}}=\frac{1}{r}\tex

1.	If pqr ≠ 0 and \({{p}^{-x}}=\frac{1}{q}~,~{{q}^{-y}}=\frac{1}{r}\text{ }\!\!~\!\!\text{ },\text{ }\!\!~\!\!\text{ }{{r}^{-z}}=\frac{1}{p}\text{ }\!\!~\!\!\text{ },\text{ }\!\!~\!\!\text{ }\)What is the value of the product of xyz?
A.	-1
B.	\(\frac{1}{pqr}\)
C.	1
D.	pqr
Answer» D. pqr

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If pqr ≠ 0 and \({{p}^{-x}}=\frac{1}{q}~,~{{q}^{-y}}=\frac{1}{r}\text{ }\!\!~\!\!\text{ },\text{ }\!\!~\!\!\text{ }{{r}^{-z}}=\frac{1}{p}\text{ }\!\!~\!\!\text{ },\text{ }\!\!~\!\!\text{ }\)What is the value of the product of xyz?

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