If \[p={{x}^{\frac{1}{3}}}+{{x}^{\frac{1}{3}}}\] , then \[{{p}^{3}}-3p\] is equal to

If \[p={{x}^{\frac{1}{3}}}+{{x}^{\frac{1}{3}}}\] , then \[{{p}^{3}}-3p

1.	If \[p={{x}^{\frac{1}{3}}}+{{x}^{\frac{1}{3}}}\] , then \[{{p}^{3}}-3p\] is equal to
A.	3
B.	\[\frac{1}{2}(x+{{x}^{-1}})\]
C.	\[x+{{x}^{-1}}\]
D.	\[2(x+{{x}^{-1}})\]
Answer» D. \[2(x+{{x}^{-1}})\]

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If \[p={{x}^{\frac{1}{3}}}+{{x}^{\frac{1}{3}}}\] , then \[{{p}^{3}}-3p\] is equal to

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