If \(\operatorname{cosec} \theta-\sin \theta=m \) and \(\sec \theta-\cos \theta=\mathbf{n}\) then what is \(m^{\frac{4}{3}} n^{\frac{2}{3}}+m^{\frac{2}{3}} n^{\frac{4}{3}}\) equal to ?

• A. 0
• B. 1
• C. mn
• D. m2n2