If ω is a cube root of unity, then find the value of the determinant \(\rm \begin{vmatrix} 1 + \omega & \omega^2 & -\omega \\\ 1 + \omega^2 & \omega & -\omega^2 \\\ \omega^2 + \omega & \omega & -\omega^2 \end{vmatrix}\) is

If ω is a cube root of unity, then find the value of the determinant

1.	If ω is a cube root of unity, then find the value of the determinant \(\rm \begin{vmatrix} 1 + \omega & \omega^2 & -\omega \\\ 1 + \omega^2 & \omega & -\omega^2 \\\ \omega^2 + \omega & \omega & -\omega^2 \end{vmatrix}\) is
A.	3ω
B.	-3ω
C.	3ω2
D.	-3ω2
Answer» E.

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If ω is a cube root of unity, then find the value of the determinant \(\rm \begin{vmatrix} 1 + \omega & \omega^2 & -\omega \\\ 1 + \omega^2 & \omega & -\omega^2 \\\ \omega^2 + \omega & \omega & -\omega^2 \end{vmatrix}\) is

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