If \[\mathbf{sin }\theta \mathbf{ =}\frac{\mathbf{p}}{\mathbf{q}}\] then \[\mathbf{cos}\theta \]equals to _________

\[\mathbf{ }\sqrt{{{q}^{2}}-{{p}^{2}}}\mathbf{ }\]

\[\frac{\sqrt{{{q}^{2}}-{{p}^{2}}}}{q}\]

\[\frac{\sqrt{{{p}^{2}}+{{q}^{2}}}}{q}\]

If \[\mathbf{sin }\theta \mathbf{ =}\frac{\mathbf{p}}{\mathbf{q}}\] th

1.	If \[\mathbf{sin }\theta \mathbf{ =}\frac{\mathbf{p}}{\mathbf{q}}\] then \[\mathbf{cos}\theta \]equals to _________
A.	\[\mathbf{ }\sqrt{{{q}^{2}}-{{p}^{2}}}\mathbf{ }\]
B.	\[\frac{\sqrt{{{q}^{2}}-{{p}^{2}}}}{q}\]
C.	\[\sqrt{{{p}^{2}}-{{q}^{2}}}\]
D.	\[\frac{\sqrt{{{p}^{2}}+{{q}^{2}}}}{q}\]
E.	None of these
Answer» C. \[\sqrt{{{p}^{2}}-{{q}^{2}}}\]

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If \[\mathbf{sin }\theta \mathbf{ =}\frac{\mathbf{p}}{\mathbf{q}}\] then \[\mathbf{cos}\theta \]equals to _________

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