If\[\mathbf{sin}\theta -\mathbf{cos}\theta =\sqrt{2}\mathbf{sin}\left( \mathbf{9}{{\mathbf{0}}^{{}^\circ }}-\theta \right)\]then \[\mathbf{cot}\theta \]is equal to:

If\[\mathbf{sin}\theta -\mathbf{cos}\theta =\sqrt{2}\mathbf{sin}\left(

1.	If\[\mathbf{sin}\theta -\mathbf{cos}\theta =\sqrt{2}\mathbf{sin}\left( \mathbf{9}{{\mathbf{0}}^{{}^\circ }}-\theta \right)\]then \[\mathbf{cot}\theta \]is equal to:
A.	\[\sqrt{2}\]
B.	0
C.	\[\sqrt{2}-1\]
D.	\[\sqrt{2}+1\]
Answer» D. \[\sqrt{2}+1\]

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If\[\mathbf{sin}\theta -\mathbf{cos}\theta =\sqrt{2}\mathbf{sin}\left( \mathbf{9}{{\mathbf{0}}^{{}^\circ }}-\theta \right)\]then \[\mathbf{cot}\theta \]is equal to:

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