If \[\mathbf{sin 2x=}\frac{\mathbf{2tan 30{}^\circ }}{\mathbf{1+ ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{ 30}}\] , then the value of \[\frac{\mathbf{1}-\mathbf{ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{x}}{\mathbf{1+ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{x}}\]is equal to____ (where\[0{}^\circ

If \[\mathbf{sin 2x=}\frac{\mathbf{2tan 30{}^\circ }}{\mathbf{1+ ta}{{

1.	If \[\mathbf{sin 2x=}\frac{\mathbf{2tan 30{}^\circ }}{\mathbf{1+ ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{ 30}}\] , then the value of \[\frac{\mathbf{1}-\mathbf{ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{x}}{\mathbf{1+ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{x}}\]is equal to____ (where\[0{}^\circ
A.	Sin x
B.	Cos 3x
C.	0
D.	1
E.	None of these
Answer» B. Cos 3x

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If \[\mathbf{sin 2x=}\frac{\mathbf{2tan 30{}^\circ }}{\mathbf{1+ ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{ 30}}\] , then the value of \[\frac{\mathbf{1}-\mathbf{ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{x}}{\mathbf{1+ta}{{\mathbf{n}}^{\mathbf{2}}}\mathbf{x}}\]is equal to____ (where\[0{}^\circ

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