If \[\mathbf{A}={{\mathbf{2}}^{x}},\mathbf{B}={{\mathbf{4}}^{\mathbf{y}}},\mathbf{C}={{\mathbf{8}}^{z}}\], where \[\mathbf{x}=0.\overline{1},\mathbf{y}=\mathbf{0}.\overline{\mathbf{4}},\mathbf{z}=\mathbf{0}.\overline{\mathbf{6}}\], then \[\mathbf{A}\times \mathbf{B}\times \mathbf{C}\]is

If \[\mathbf{A}={{\mathbf{2}}^{x}},\mathbf{B}={{\mathbf{4}}^{\mathbf{y

1.	If \[\mathbf{A}={{\mathbf{2}}^{x}},\mathbf{B}={{\mathbf{4}}^{\mathbf{y}}},\mathbf{C}={{\mathbf{8}}^{z}}\], where \[\mathbf{x}=0.\overline{1},\mathbf{y}=\mathbf{0}.\overline{\mathbf{4}},\mathbf{z}=\mathbf{0}.\overline{\mathbf{6}}\], then \[\mathbf{A}\times \mathbf{B}\times \mathbf{C}\]is
A.	8
B.	2
C.	16
D.	4
Answer» B. 2

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If \[\mathbf{A}={{\mathbf{2}}^{x}},\mathbf{B}={{\mathbf{4}}^{\mathbf{y}}},\mathbf{C}={{\mathbf{8}}^{z}}\], where \[\mathbf{x}=0.\overline{1},\mathbf{y}=\mathbf{0}.\overline{\mathbf{4}},\mathbf{z}=\mathbf{0}.\overline{\mathbf{6}}\], then \[\mathbf{A}\times \mathbf{B}\times \mathbf{C}\]is

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