If \[lo{{g}_{10}}8=x\], then \[lo{{g}_{10}}\left( \frac{1}{80} \right)\] is equal to:

\[{{\left( 1+x \right)}^{-1}}\]

If \[lo{{g}_{10}}8=x\], then \[lo{{g}_{10}}\left( \frac{1}{80} \right)

1.	If \[lo{{g}_{10}}8=x\], then \[lo{{g}_{10}}\left( \frac{1}{80} \right)\] is equal to:
A.	\[-\left( 1+x \right)\]
B.	\[{{\left( 1+x \right)}^{-1}}\]
C.	\[\frac{a}{10}\]
D.	\[\frac{1}{10a}\]
Answer» B. \[{{\left( 1+x \right)}^{-1}}\]

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If \[lo{{g}_{10}}8=x\], then \[lo{{g}_{10}}\left( \frac{1}{80} \right)\] is equal to:

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