If \[\left( \mathbf{1}+\mathbf{sinx} \right)\left( \mathbf{l}+\mathbf{siny} \right)\left( \mathbf{l}+\mathbf{sinz} \right)\]\[=\left( \mathbf{l}-\mathbf{sinx} \right)\left( \mathbf{l}-\mathbf{siny} \right)\left( \mathbf{l}-\mathbf{sinz} \right)\] then each side is equal to

\[\pm cosx\text{ }cosy\text{ }cosz\]

\[\pm sinx\text{ }cosy\text{ }cosz\]

If \[\left( \mathbf{1}+\mathbf{sinx} \right)\left( \mathbf{l}+\mathbf{

1.	If \[\left( \mathbf{1}+\mathbf{sinx} \right)\left( \mathbf{l}+\mathbf{siny} \right)\left( \mathbf{l}+\mathbf{sinz} \right)\]\[=\left( \mathbf{l}-\mathbf{sinx} \right)\left( \mathbf{l}-\mathbf{siny} \right)\left( \mathbf{l}-\mathbf{sinz} \right)\] then each side is equal to
A.	\[\pm cosx\text{ }cosy\text{ }cosz\]
B.	\[\pm \sin x\,\sin y\,sinz\]
C.	\[\pm sinx\text{ }cosy\text{ }cosz\]
D.	\[\pm \sin x\,siny\,cosz\]
Answer» B. \[\pm \sin x\,\sin y\,sinz\]

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If \[\left( \mathbf{1}+\mathbf{sinx} \right)\left( \mathbf{l}+\mathbf{siny} \right)\left( \mathbf{l}+\mathbf{sinz} \right)\]\[=\left( \mathbf{l}-\mathbf{sinx} \right)\left( \mathbf{l}-\mathbf{siny} \right)\left( \mathbf{l}-\mathbf{sinz} \right)\] then each side is equal to

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