MCQOPTIONS
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| 1. |
If \(\frac{{\sin \left( {x\; + \;y} \right)}}{{\sin \left( {x\; - \;y} \right)}} = \;\frac{{a\; + \;b}}{{a\; - \;b}}\) then what is \(\frac{{\tan x}}{{\tan y}}\) equal to? |
| A. | \(\frac{a}{b}\) |
| B. | \(\frac{b}{a}\) |
| C. | \(\frac{{a + b}}{{a - b}}\) |
| D. | \(\frac{{a - b}}{{a + b}}\) |
| Answer» B. \(\frac{b}{a}\) | |