1.

If \(\frac{{\sin \left( {x\; + \;y} \right)}}{{\sin \left( {x\; - \;y} \right)}} = \;\frac{{a\; + \;b}}{{a\; - \;b}}\) then what is \(\frac{{\tan x}}{{\tan y}}\) equal to?

A. \(\frac{a}{b}\)
B. \(\frac{b}{a}\)
C. \(\frac{{a + b}}{{a - b}}\)
D. \(\frac{{a - b}}{{a + b}}\)
Answer» B. \(\frac{b}{a}\)


Discussion

No Comment Found