MCQOPTIONS
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| 1. |
If \({[{\{ {(\frac{2}{3})^3}\} ^{(2x + 3)}}]^{\frac{{ - 3}}{4}}} = {[{\{ {(\frac{2}{3})^{\frac{2}{3}}}\} ^{(3x + 7)}}]^{\frac{{ - 6}}{5}}}\), then the value of \(\sqrt {2 - 42x}\) is: |
| A. | 5 |
| B. | 4 |
| C. | 6 |
| D. | 3 |
| Answer» B. 4 | |