If \(\frac{1}{{x\; + \;2}} = \frac{3}{{y\; + \;3}} = \frac{{1331}}{{z\; + \;1331}} = \frac{1}{3}\), then what is the value of \(\frac{x}{{x\; + \;1}} + \frac{4}{{y\; + \;2}} + \frac{z}{{z\; + \;2662}}\)

• A. 0
• B. 1
• C. 3/2
• D. 3