If f(x) = xm sin(1/x), x ≠ 0, f(0) = 0 then the minimum value of m for which f is derivable at x = 0 and also \(\frac{{df}}{{dx}}\) is continuous at x = 0 is

If f(x) = xm sin(1/x), x ≠ 0, f(0) = 0 then the minimum value of m f

1.	If f(x) = xm sin(1/x), x ≠ 0, f(0) = 0 then the minimum value of m for which f is derivable at x = 0 and also \(\frac{{df}}{{dx}}\) is continuous at x = 0 is
A.	m = 1
B.	m = 4
C.	m = 2
D.	m = 3
Answer» E.

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If f(x) = xm sin(1/x), x ≠ 0, f(0) = 0 then the minimum value of m for which f is derivable at x = 0 and also \(\frac{{df}}{{dx}}\) is continuous at x = 0 is

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