If ey + xy = e, the ordered pair \(\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}},\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)\) at x = 0 is equal to:

\(\left( {\frac{1}{{\rm{e}}},\frac{1}{{{{\rm{e}}^2}}}} \right)\)

\(\left( {\frac{1}{{\rm{e}}}, - \frac{1}{{{{\rm{e}}^2}}}} \right)\)

\(\left( { - \frac{1}{{\rm{e}}},\frac{1}{{{{\rm{e}}^2}}}} \right)\)

\(\left( { - \frac{1}{{\rm{e}}}, - \frac{1}{{{{\rm{e}}^2}}}} \right)\)

If ey + xy = e, the ordered pair \(\left( {\frac{{{\rm{dy}}}}{{{\rm{dx

1.	If ey + xy = e, the ordered pair \(\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}},\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)\) at x = 0 is equal to:
A.	\(\left( {\frac{1}{{\rm{e}}}, - \frac{1}{{{{\rm{e}}^2}}}} \right)\)
B.	\(\left( { - \frac{1}{{\rm{e}}},\frac{1}{{{{\rm{e}}^2}}}} \right)\)
C.	\(\left( {\frac{1}{{\rm{e}}},\frac{1}{{{{\rm{e}}^2}}}} \right)\)
D.	\(\left( { - \frac{1}{{\rm{e}}}, - \frac{1}{{{{\rm{e}}^2}}}} \right)\)
Answer» C. \(\left( {\frac{1}{{\rm{e}}},\frac{1}{{{{\rm{e}}^2}}}} \right)\)

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If ey + xy = e, the ordered pair \(\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}},\frac{{{{\rm{d}}^2}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^2}}}} \right)\) at x = 0 is equal to:

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