If ∫esec x (secx tanx f(x) + (secx tanx + sec2 x)) dx = esec x f(x) + C, then a possible choice of f(x) is:

\({\rm{secx}} - {\rm{tanx}} - \frac{1}{2}\)

\({\rm{secx}} + {\rm{tanx}} + \frac{1}{2}\)

\({\rm{secx}} + {\rm{tanx}} - \frac{1}{2}\)

\({\rm{xsecx}} + {\rm{tanx}} + \frac{1}{2}\)

If ∫esec x (secx tanx f(x) + (secx tanx + sec2 x)) dx = esec x f(x)

1.	If ∫esec x (secx tanx f(x) + (secx tanx + sec2 x)) dx = esec x f(x) + C, then a possible choice of f(x) is:
A.	\({\rm{secx}} + {\rm{tanx}} + \frac{1}{2}\)
B.	\({\rm{secx}} - {\rm{tanx}} - \frac{1}{2}\)
C.	\({\rm{secx}} + {\rm{tanx}} - \frac{1}{2}\)
D.	\({\rm{xsecx}} + {\rm{tanx}} + \frac{1}{2}\)
Answer» B. \({\rm{secx}} - {\rm{tanx}} - \frac{1}{2}\)

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If ∫esec x (secx tanx f(x) + (secx tanx + sec2 x)) dx = esec x f(x) + C, then a possible choice of f(x) is:

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